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Section 1.6 Limits with Infinite Outputs (LT6)
Learning Outcomes
Determine limits of functions approaching vertical asymptotes.
Subsection 1.6.1 Activities
Activity 1.6.1 .
Diagram Exploration Keyboard Controls
Key
Action
Enter, A
Activate keyboard driven exploration
B
Activate menu driven exploration
Escape
Leave exploration mode
Cursor down
Explore next lower level
Cursor up
Explore next upper level
Cursor right
Explore next element on level
Cursor left
Explore previous element on level
X
Toggle expert mode
W
Extra details if available
Space
Repeat speech
M
Activate step magnification
Comma
Activate direct magnification
N
Deactivate magnification
Z
Toggle subtitles
C
Cycle contrast settings
T
Monochrome colours
L
Toggle language (if available)
K
Kill current sound
Y
Stop sound output
O
Start and stop sonification
P
Repeat sonification output
Figure 24. The graph of \(1/x^2\text{.}\)
(a)
Which of the following best describes the limit as
\(x\) approaches zero in the graph?
The limit is positive infinity
This limit is negative infinity
(b)
Which of the following best describes the relationship between the line
\(x=0 \) and the graph of the function?
The line
\(x=0\) is a horizontal asymptote for the function
The function is not continuous at the point
\(x=0\)
The function is moving away from the line
\(x=0\)
The function is getting closer and closer to the line
\(x=0\)
The function has a jump in outputs around
\(x=0\)
Definition 1.6.2 .
A function has a
vertical asymptote at
\(x=a\) when
\begin{equation*}
\lim_{x\to a} f(x) = + \infty
\end{equation*}
\begin{equation*}
\lim_{x\to a} f(x) = - \infty
\end{equation*}
The limit being equal to positive infinity means that we can make the output of
\(f(x)\) as large a positive number as we want as long as we are sufficiently close to
\(x=a\text{.}\) Similarly, the limit being equal to negative infinity means that we can make the output of
\(f(x)\) as large a negative number as we want as long as we are sufficiently close to
\(x=a\text{.}\)
Activity 1.6.3 .
Select all of the following graphs which illustrate functions with vertical asymptotes.
Diagram Exploration Keyboard Controls
Key
Action
Enter, A
Activate keyboard driven exploration
B
Activate menu driven exploration
Escape
Leave exploration mode
Cursor down
Explore next lower level
Cursor up
Explore next upper level
Cursor right
Explore next element on level
Cursor left
Explore previous element on level
X
Toggle expert mode
W
Extra details if available
Space
Repeat speech
M
Activate step magnification
Comma
Activate direct magnification
N
Deactivate magnification
Z
Toggle subtitles
C
Cycle contrast settings
T
Monochrome colours
L
Toggle language (if available)
K
Kill current sound
Y
Stop sound output
O
Start and stop sonification
P
Repeat sonification output
Activity 1.6.5 .
Notice that as
\(x\) goes to 0, the value of
\(x^2\) goes to 0 but the value of
\(1/x^2\) goes to infinity. What is the best explanation for this behavior?
When dividing by an increasingly small number we get an increasing big number
When dividing by an increasingly large number we get an increasing small number
A rational function always has a vertical asymptote
A rational function always has a horizontal asymptote
Activity 1.6.7 .
Consider the rational function
\(f(x) = \dfrac{2}{x-3} \text{.}\) Which of the following options best describes the limits as x approaches
\(3\) from the right and from the left?
As
\(x \to 3^+\text{,}\) the limit DNE, but as
\(x \to 3^-\) the limit is
\(-\infty\text{.}\)
As
\(x \to 3^+\text{,}\) the limit is
\(+\infty\text{,}\) but as
\(x \to 3^-\) the limit is
\(-\infty\text{.}\)
As
\(x \to 3^+\text{,}\) the limit is
\(+\infty\text{,}\) but as
\(x \to 3^-\) the limit is
\(+\infty\text{.}\)
As
\(x \to 3^+\text{,}\) the limit is
\(-\infty\text{,}\) but as
\(x \to 3^-\) the limit is
\(-\infty\text{.}\)
As
\(x \to 3^+\text{,}\) the limit DNE and as
\(x \to 3^-\) the limit DNE.
Activity 1.6.9 .
Consider the function
\(f(x)=\dfrac{x^2-1}{x-1}\text{.}\) The line
\(x=1\) is NOT a vertical asymptote for
\(f(x)\text{.}\) Why?
When
\(x\) is not equal to
\(1\text{,}\) we can simplify the fraction to
\(x-1\text{,}\) so the limit is
\(1\text{.}\)
When
\(x\) is not equal to
\(1\text{,}\) we can simplify the fraction to
\(x+1\text{,}\) so the limit is
\(2\text{.}\)
The function is always equal to
\(x+1\text{.}\)
The function is always equal to
\(x-1\text{.}\)
Activity 1.6.11 .
Find all the vertical asymptotes of the following rational functions.
(a)
\(y = \dfrac{3x-4}{7x+1}\)
(b)
\(y= \dfrac{x^2+10x+24}{x^2-2x+1}\)
(c)
\(y= \dfrac{(x^2-4)(x^2+1)}{x^6}\)
(d)
\(y= \dfrac{2x+1}{2x^2+8x-10}\)
Activity 1.6.12 .
Explain and demonstrate how to find the value of each limit.
(a)
\begin{equation*}
\lim_{x\to-3^- } \dfrac{{\left(x + 4\right)}^{2} {\left(x - 2\right)}}{{\left(x + 3\right)} {\left(x - 5\right)}}
\end{equation*}
(b)
\begin{equation*}
\lim_{x\to-3^+ } \dfrac{{\left(x + 4\right)}^{2} {\left(x - 2\right)}}{{\left(x + 3\right)} {\left(x - 5\right)}}
\end{equation*}
(c)
\begin{equation*}
\lim_{x\to-3 } \dfrac{{\left(x + 4\right)}^{2} {\left(x - 2\right)}}{{\left(x + 3\right)} {\left(x - 5\right)}}
\end{equation*}
Activity 1.6.13 .
The graph below represents the function
\(f(x) = \displaystyle\dfrac{(x+2)(x+4)}{x^2+3x-4}\text{.}\)
Diagram Exploration Keyboard Controls
Key
Action
Enter, A
Activate keyboard driven exploration
B
Activate menu driven exploration
Escape
Leave exploration mode
Cursor down
Explore next lower level
Cursor up
Explore next upper level
Cursor right
Explore next element on level
Cursor left
Explore previous element on level
X
Toggle expert mode
W
Extra details if available
Space
Repeat speech
M
Activate step magnification
Comma
Activate direct magnification
N
Deactivate magnification
Z
Toggle subtitles
C
Cycle contrast settings
T
Monochrome colours
L
Toggle language (if available)
K
Kill current sound
Y
Stop sound output
O
Start and stop sonification
P
Repeat sonification output
Figure 25. The graph of \(f(x)\)
(a)
Explain the behavior of
\(f(x)\) at
\(x=-4 \text{.}\)
(b)
Find the vertical asymptote(s) of
\(f(x)\text{.}\) First, guess it from the graph. Then, prove that your guess is right using algebra.
(c)
Find the horizontal asymptote(s) of
\(f(x)\text{.}\) First, guess it from the graph. Then, prove that your guess is right using algebra.
(d)
Use limit notation to describe the behavior of
\(f(x)\) at its asymptotes.
Activity 1.6.14 .
Consider the following rational function.
\begin{equation*}
r(x) = \dfrac{ 5 \, {\left(x - 3\right)} {\left(x - 6\right)}^{3} }{ 6 \, {\left(x + 2\right)}^{3} {\left(x - 3\right)} }
\end{equation*}
(a)
Explain how to find the horizontal asymptote(s) of
\(r(x)\text{,}\) if there are any. Then express your findings using limit notation.
(b)
Explain how to find the hole(s) of
\(r(x)\text{,}\) if there are any. Then express your findings using limit notation.
(c)
Explain how to find the vertical asymptote(s) of
\(r(x)\text{,}\) if there are any. Then express your findings using limit notation.
(d)
Draw a rough sketch of
\(r(x)\) that showcases all the limits that you have found above.
Activity 1.6.15 .
You want to draw a function with all these properties.
\(\displaystyle \displaystyle \lim_{x\to 3} f(x)=5\)
\(\displaystyle f(3)=0 \)
\(\displaystyle \displaystyle \lim_{x\to 0^{-}} f(x) = -\infty\)
\(\displaystyle \displaystyle \lim_{x\to 0^{+}} f(x) = 0\)
\(\displaystyle \displaystyle \lim_{x\to +\infty} f(x) = 2\)
(a)
At which
\(x\) values will the limit not exist?
(b)
What are the asymptotes of this function?
(c)
At which
\(x\) values will the function be discontinuous?
(d)
Draw the graph of one function with all the properties above. Make sure that your graph is a function! You only need to draw a graph, writing a formula would be very challenging!
Subsection 1.6.2 Videos
Figure 26. Video for LT6
Subsection 1.6.3 Exercises